The formula to apply is ;
A= P{1+r/n}^nt
where
A= amount at the end of the period
P= starting amount = $1200
r= rate of interest =4%= 0.04
n=number of compoundings per annum = 1
t= time period = 3
Using the values in the equation as;
A= 1200{ 1+ 0.04} ^3
A= 1200{1.04}^3
A= $1349.84
Answer
Amount = $1349.84