For two lines to be perpendicular, the multiplication of their slopes must be equal to -1. Then, two equations in slope-intercept form that are perpendicular could be:
The slope-intercept form is represented as:
[tex]y=mx+b[/tex]Where m is the slope and b is the y-intercept.
[tex]y=-\frac{4}{5}x+3,y=\frac{5}{4}x+3[/tex]We have that the product of their slopes is:
[tex]m_1=-\frac{4}{5},m_2=\frac{5}{4}\Rightarrow m_{1\cdot}m_2=-\frac{4}{5}\cdot\frac{5}{4}=-1[/tex]Thus, these lines are perpendicular and are in the form of a slope-intercept form.
They also have the same y-intercept (y = 3)