Given expression is
[tex](3m^{-4})^3(3m^5)[/tex]We have to simplify this expression.
By power of power rule,
[tex](3m^{-4})^3=3^3m^{-12}=27m^{-12}[/tex]Then the answer is
[tex]D.\frac{81}{m^7}[/tex]Since,
[tex](3m^{-4})^3(3m^5)=27\times3m^{-12+5}=81m^{-7}[/tex]