A chemist performs an experiment in which she compresses an air sample and then measures its pressure. She records her results in the following table:Volume (cm)³100.050.025.0Pressure (kPa)33.3 66.7 133.2 If the chemist continues to compress the air to a volume of 12.5 cm³, what will itspressure most likely be?A. 266.4 kPaB. 366.4 kPaC. 212.2 kPaD. 12.5 kPa



Answer :

Apply Boyle's law:

P1 V1 = P2 V2 =P3 V3 = P4 V4

(33.3)(100) = P4 ( 12.5 )

3330 = 12.5 P4

3330/12.5 = P4

P4 = 266.4 kPA

Answer:

A. 266.4 kPa