SOLUTION
From the question the height of the can is 4 ft and its diameter is 1.5 ft
The radius r of the can since it is shaped like a cylinder is
[tex]r=\frac{diameter\text{ }}{2}=\frac{1.5}{2}=0.75\text{ ft }[/tex]
The quantity or the contents of the container is the volume V of a cylinder, which is
[tex]\begin{gathered} V=\pi r^2h \\ V=\pi\times0.75^2\times4 \\ V=7.06858 \\ V=7.1\text{ ft}^3 \end{gathered}[/tex]
Now, we are told that the average weight of aluminium cans is 37 ounces per cubic feet.
This means that 1 cubic feet of aluminium weighs 37 ounces. But the contents is approximately 7.1 cubic feet. Hence 7.1 cubic feet of aluminium will weigh
[tex]\begin{gathered} 7.1\times37 \\ =262.7\text{ ounces } \end{gathered}[/tex]
Hence the answer is approximately 262.7 ounces
