SOLUTION
[tex]\begin{gathered} Given \\ x^{-\frac{5}{3}} \end{gathered}[/tex][tex]\begin{gathered} Appying\text{ negative exponential rule;} \\ ie\text{ x}^{-a}=\frac{1}{x^a} \end{gathered}[/tex][tex]x^{-\frac{5}{3}}=\frac{1}{x^{\frac{5}{3}}}[/tex][tex]\begin{gathered} Applying\text{ fractional exponential rule;} \\ ie\text{ x}^{\frac{a}{b}}=\sqrt[b]{x}^a \end{gathered}[/tex][tex]x^{-\frac{5}{3}}=\frac{1}{x^{\frac{5}{3}}}=\frac{1}{\sqrt[3]{x^5}}[/tex]Final answer: