Notice that the irregular figure can be separated into three rectangles:
Find the area of each rectangle and add them all together to find the area of the irregular figure:
[tex]\begin{gathered} A_1=7in\times8in=56in^2 \\ A_2=22in\times7in=154in^2 \\ A_3=5in\times6in=30in^2 \end{gathered}[/tex]
Then, the area of the irregular figure, is:
[tex]A=56in^2+154in^2+30in^2=240in^2[/tex]
Therefore, the area of the composite figure, is:
[tex]240\text{ }in^2[/tex]
