Answer :

[tex]y=x^2-8x+12[/tex]

For x = -2

[tex]\begin{gathered} x=-2 \\ y(1)=(1)^2-8(1)+12=1-8+12=5 \\ Point_{}A\colon(1,5) \\ --------- \\ x=3 \\ y(2)=3^2-8(3)+12=9-24+12=-3 \\ Point_{}B\colon(3,-3) \end{gathered}[/tex]

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