The sum of consecutive integers 1,2,3.. n is given by the formula 2/2n(n+1) how many consecutive integers, starting with 1, must be added to get a sum 946?



Answer :

Answer:

Explanation:

Given the sequence 1, 2, 3,..., n,

where;

[tex]\begin{gathered} a_1=\text{first term}=1 \\ d=\text{common difference }=2-1=1 \end{gathered}[/tex]

Given the below formula for the sum of consecutive integers;

[tex]S_n=\frac{2}{2n(n+1)}[/tex]

Given 946, as the required sum, let's go-ahead and substitute it into the formula and cross multiply as seen below;

[tex]\begin{gathered} \\ \\ \end{gathered}[/tex]