The electromagnetic frequency of broadcasting is 97.73 MHz.
We need to know about electromagnetic energy to solve the problem. The electromagnetic energy of radiated photons can be calculated by frequency. It can be determined as
E = h . f
where E is energy, h is Max Planck's constant (6.6 x 10¯³⁴ Js) and f is the frequency.
From the question above, the given parameter is
E = 6.45 x 10¯²⁹ kJ / photon = 6.45 x 10¯²⁶ J / photon
Thus, the frequency of a photon should follows
E = h . f
6.45 x 10¯²⁶ = 6.6 x 10¯³⁴ . f
f = 6.45 x 10¯²⁶ / (6.6 x 10¯³⁴)
f = 97727272 Hz
f = 97.73 MHz
For more on electromagnetic energy at: https://brainly.com/question/15946945
#SPJ4
Answer:
Explanation:
Given:
E = 6.45·10⁻²⁹ kJ / photon = 6.45·10⁻²⁶ J / photon
h = 6.63·10⁻³⁴ J·s - Planck's constant
____________________
f - ?
The frequency:
f = E / h
f = 6.45·10⁻²⁶ / 6.63·10⁻³⁴ ≈ 97·10⁶ Hz or f = 97 MHz