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9zxaA14ePolynomialThe parallelogram shown below is transformed. Identify the type of transformation thatoccurred, then write the algebraic rule that describes the transformation. Use a table like theone shown to help you.(5) = ?Copy the text below into the answer space and then replace the _ with your answer.Expression23-(1-1)Op 1 OpType of Transformation:Algebraic Representation: *Get reald67850.0 mLITGGPre-ImageImageWhathappensto x?Whathappensto y?E'HX3FHIG'GEH'9.Enter your answer

9zxaA14ePolynomialThe parallelogram shown below is transformed Identify the type of transformation thatoccurred then write the algebraic rule that describes the class=


Answer :

Given the parallelogram and its image

For the point E'

Pre image is E = (2 , 5 )

Image is E' = ( -2 , -5 )

What happen to x? is multiplicative inverse ( multiplied by -1)

What happen to y? is multiplicative inverse ( multiplied by -1)

For the row of F' ;

Pre - image is F = (4 , 8 )

Image is F' = ( -4 , -8 )

What happen to x? is multiplicative inverse ( multiplied by -1)

What happen to y? is multiplicative inverse ( multiplied by -1)

For the row of G' :

Pre - image is G = ( 6 , 5 )

Image is G' = ( -6 , -5 )

What happen to x? is multiplicative inverse ( multiplied by -1)

What happen to y? is multiplicative inverse ( multiplied by -1)

For the row of H' :

Pre - image is H = ( 4 , 2 )

Image is H' = ( -4 , -2 )

What happen to x? is multiplicative inverse ( multiplied by -1)

What happen to y? is multiplicative inverse ( multiplied by -1)

so,

As shown, Type of Transformation: is reflection over the point ( 0 , 0 )

Or can be written reflection Through the origin

Algebraic Representation: ( -x , -y )

the rule of translation

(x , y ) → ( -x , -y)

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