Answer :
Solution:
Let A be the first aircraft
Let B be the second aircraft
Let C be the third aircraft
Here is the information that is given in the question:
The first aircraft has 65 more seats than the second aircraft:
A = B + 65
The third aircraft has 41 fewer seats than the second aircraft
C = B - 41
their total number of seats is 402
A + B + C = 402
Now substitute the values in the 1st and 2nd equations into the 3rd.
(B+65) + B + (B-41) = 402
this is equivalent to:
3B + (65-41) = 402
this is equivalent to:
3B + 24 = 402
this is equivalent to:
3B = 402 - 24 = 378
solving for B, we get:
[tex]B\text{ = }\frac{378}{3}=126[/tex]We can conclude that the correct answer is:
first aircraft A:
A = B + 65 = 126 + 65 = 191
that is:
A = 191
second aircraft:
B = 126
third aircraft:
C = B - 41 = 126 - 41 = 85
that is:
C = 85
