Answer :

30+2|3 times -2+2|

we have the expression

[tex]30+2\cdot\lvert3\cdot(-2)+2\rvert[/tex]

solve the interior of the absolute value first

multiplication

[tex]\begin{gathered} 30+2\cdot\lvert-6+2\rvert \\ 30+2\cdot\lvert-4\rvert \\ 30+2\cdot(4) \end{gathered}[/tex]

Solve the multiplication

30+8

adds the numbers

38

the answer is 38