30+2|3 times -2+2|
we have the expression
[tex]30+2\cdot\lvert3\cdot(-2)+2\rvert[/tex]solve the interior of the absolute value first
multiplication
[tex]\begin{gathered} 30+2\cdot\lvert-6+2\rvert \\ 30+2\cdot\lvert-4\rvert \\ 30+2\cdot(4) \end{gathered}[/tex]Solve the multiplication
30+8
adds the numbers
38