Answer :
Answer
The percent composition of Fe = 26.73%
The percent composition of C = 22.99%
The percent composition of H = 4.34%
The percent composition of O = 45.94%
Explanation
Given:
The compound is Fe(C₂H₃O₂)₃
What to find:
The percent composition of each of the elements in Fe(C₂H₃O₂)₃
Step-by-step solution:
Step 1: Calculate the total of Fe(C₂H₃O₂)₃ using the atomic masses of each of the elements in the periodic table.
Atomic mass of: (H = 1.008, C = 12.01, O = 15.999, Fe = 55.845)
Total mass of Fe(C₂H₃O₂)₃ = Fe + 4(C) + 9(H) + 6(O)
Total mass of Fe(C₂H₃O₂)₃ = 55.845 + 4(12.01) + 9(1.008) + 6(15.999)
Total mass of Fe(C₂H₃O₂)₃ = 55.845 + 48.04 + 9.072 + 95.994
Total mass of Fe(C₂H₃O₂)₃ = 208.951
Step 2: Determine the percent composition of Fe in Fe(C₂H₃O₂)₃
Mass of Fe in Fe(C₂H₃O₂)₃ = 55.845
[tex]\begin{gathered} Percent\text{ }composition\text{ }of\text{ }Fe=\frac{Mass\text{ }of\text{ }Fe}{Total\text{ }mass}\times100\% \\ \\ Percent\text{ }composition\text{ }of\text{ }Fe=\frac{55.845}{208.951}\times100\% \\ \\ Percent\text{ }composition\text{ }of\text{ }Fe=26.73\% \end{gathered}[/tex]The percent composition of Fe = 26.73%
Step 3: Determine the percent composition of C in Fe(C₂H₃O₂)₃
Mass of C in Fe(C₂H₃O₂)₃ = 4(C) = 48.04
[tex]\begin{gathered} Percent\text{ }composition\text{ }of\text{ }C=\frac{Mass\text{ }of\text{ }C}{Total\text{ }mass}\times100\% \\ \\ Percent\text{ }composition\text{ }of\text{ }C=\frac{48.04}{208.951}\times100\% \\ \\ Percent\text{ }composition\text{ }of\text{ }C=22.99\% \end{gathered}[/tex]The percent composition of C = 22.99%
Step 4: Determine the percent composition of H in Fe(C₂H₃O₂)₃
Mass of H in Fe(C₂H₃O₂)₃ = 9(H) = 9.072
[tex]\begin{gathered} Percent\text{ }composition\text{ }of\text{ }H=\frac{Mass\text{ }of\text{ }H}{Total\text{ }mass}\times100\% \\ \\ Percent\text{ }composition\text{ }of\text{ }H=\frac{9.072}{208.951}\times100\% \\ \\ Percent\text{ }composition\text{ }of\text{ }H=4.34\% \end{gathered}[/tex]The percent composition of H = 4.34%
Step 5: Determine the percent composition of O in Fe(C₂H₃O₂)₃
Mass of O in Fe(C₂H₃O₂)₃ = 6(O) = 95.994
[tex]\begin{gathered} Percent\text{ }composition\text{ }of\text{ }O=\frac{Mass\text{ }of\text{ }O}{Total\text{ }mass}\times100\% \\ \\ Percent\text{ }composition\text{ }of\text{ }O=\frac{95.994}{208.951}\times100\% \\ \\ Percent\text{ }composition\text{ }of\text{ }O=45.94\% \end{gathered}[/tex]The percent composition of O = 45.94%
