Answer :

Given that D is the midpoint of AB, and the coordinate of A and B are;

[tex]\begin{gathered} A=(5,-6) \\ B=(5,10) \end{gathered}[/tex]

Note: The mid point x of two points x1 and x2 can be derived from;

[tex]x=\frac{x_1+x_2}{2}[/tex]

The mid point of AB is;

[tex]\begin{gathered} D=(\frac{5+5}{2},\frac{-6+10}{2}) \\ D=(5,2) \end{gathered}[/tex]

E is the midpoint of DA, the mid point of D and A is;

[tex]\begin{gathered} E=(\frac{5+5}{2},\frac{-6+2}{2}) \\ E=(\frac{10}{2},\frac{-4}{2}) \\ E=(5,-2) \end{gathered}[/tex]

The coordinates of E is;

[tex]E=(5,-2)[/tex]

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