Answer :
To obtain zinc chloride, we have to react zinc and chlorine (Cl2), so let's state the chemical reaction:
[tex]Zn+Cl_2\to ZnCl_2.[/tex]First, let's convert 0.254 grams of zinc (Zn) to moles using its molar mass which you can see in the periodic table: molar mass of Zn = 65.37 g/mol:
[tex]\text{0}.254g\text{ Zn}\cdot\frac{1\text{ mol Zn}}{65.37\text{ g Zn}}=3.89\cdot10^{-3}mole\text{s Zn.}[/tex]You can see in the reaction that 1 mol of Zn reacted, produces 1 mol of ZnCl2 (zinc chloride), so the molar ratios between these two compounds are 1:1, so we're producing from 3.89 x 10 ^(-3) moles of Zn, 3.89 x 10^(-3) moles of ZnCl2. Based on this value, we have to convert it to mass in grams using the molar mass of zinc chloride which is 136.17 g/mol:
[tex]3.89\cdot10^{-3\text{ }}molesZnCl_2\cdot\frac{136.17gZnCl_2\text{ }}{1\text{ mol }ZnCl_2}=0.5297\text{ g }ZnCl_2\approx0.530\text{ g }ZnCl_2.[/tex]The answer is that we're producing 0.530 grams of zinc chloride from 0.254 grams of zinc reacted.
