a 50.0-g projectile is launched with a horizontal velocity of 647 m/s from a 4.65-kg launcher moving in the same direction at 2.00 m/s. what is the velocity of the launcher after the projectile is launched?



Answer :

By using concept of conservation of momentum, we can calculate that the velocity of the launcher after the projectile is -4.9 m/s .

According to the conservation of momentum, the total momentum before launching would be same as after launching.

It means,

before launched (M1V1 + M2V2)  =  after launched (M1V1 + M2V2)

where, M1, V1 is the mass and velocity of launcher respectively, and

M2, V2 is the mass and velocity of the projectile object.

Now, putting the appropriate values,

 4.65x2 + 0.05x2  = 4.65xV1 + 0.05x647

 4.65xV1 = 9.4 - 32.35

 V1 = -22.95 / 4.65

 V1 = -4.9 m/s

Hence the velocity of the launcher is -4.9 m/s after the projectile is launched.

To learn more about conservation of momentum, visit here

https://brainly.com/question/3920210

#SPJ4

Other Questions