what is the length of a simple pendulum that oscillates with a period of 1.60 s on earth, where the acceleration due to gravity is 9.80 m/s2, and on mars, where the acceleration due to gravity is 3.70 m/s2?



Answer :

By using simple harmonic motion concept, The length of a simple pendulum on earth will be 63.6 cm.

Simple pendulum exhibits  simple harmonic motion. According to the simple harmonic motion we have,

Length of pendulum (L) = [tex]\frac{T^{2}g }{4\pi ^{2} }[/tex]

where, T is time period of the pendulum and g is the gravity.

at earth we have g value 9.8 m/s^2 . g is also considered as a acceleration due to gravitational force.

Keeping the appropriate values, we get

Length of pendulum (L)  = [tex]\frac{1.6^{2} * 9.8 }{4 * 3.14^{2} }[/tex]

L = 0.636 meter = 0.636x100 cm       (1 meter = 100 centimeter)

Hence the length of the pendulum will be 63.6 cm.

To learn more on simple harmonic motion, visit here

https://brainly.com/question/17315536

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