Step 1
If the number is n, we will write the statement in equation form.
n=3
The quotient of the number cubed and nine is:
[tex]\frac{n^3}{9}[/tex]Two less than this quotient is:
[tex]\frac{n^3}{9}-2[/tex]The quotient of the number cubed and nine is Two less than this quotient and Increased by 12 is;
[tex]\frac{n^3}{9}-2+12=\frac{n^3}{9}+10[/tex]Step 2
Solve when n =3
[tex]\begin{gathered} \frac{3^3}{9}+10=\frac{27}{9}+10 \\ =3+10=13 \end{gathered}[/tex]when n=3, the expression has a value of 13
Therefore, the answers will be;
[tex]1)\text{The correct expression is }\frac{n^3}{9}-2+12[/tex][tex]2)One\text{ of the steps of }\det er\min ing\text{ the value of n when n=3 is 3-2+12}[/tex][tex]3)\text{The value of n, when n=3 is 13}[/tex]