Answer :
1) List the known quantities.
Sample: gas.
Volume 1: 253.0 mL.
Pressure 1: 842.30 mmHg.
Temperature 1: 39.1 ºC.
Pressure 2: 162.40 mmHg.
Volume 2: 795.0 mL
Temperature 2: unknown.
2) Convert units.
2.1- Convert ºC to K.
[tex]K=ºC+273.15[/tex][tex]K=39.1\text{ }ºC+273.15=312.25\text{ }K[/tex]2.2- Convert mmHg to atm
1 atm = 760 mmHg
[tex]atm=842.30\text{ }mmHg*\frac{1\text{ }atm}{760\text{ }mmHg}=1.1083\text{ }atm[/tex][tex]atm=162.40\text{ }mmHg*\frac{1\text{ }atm}{760\text{ }mmHg}=0.21368\text{ }atm[/tex]3) Set the equation.
[tex]\frac{P1V1}{T1}=\frac{P2V2}{T2}[/tex]4) Plug in the known quantities and solve for T2.
[tex]T2=\frac{P2V2T1}{P1V1}[/tex][tex]T2=\frac{(0.21368\text{ }atm)(0.7950\text{ }L)(312.25\text{ }K)}{(1.1083\text{ }atm)(0.2530\text{ }L)}[/tex][tex]T2=189.17\text{ }K[/tex]5) Convert K to ºC.
[tex]ºC=K-273.15[/tex][tex]ºC=189.17\text{ }K-273.15[/tex][tex]ºC=-83.9\text{ }ºC[/tex]The final temperature is -83.9 ºC.
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