Answer :

[tex]\begin{gathered} From\text{ the given question above} \\ \csc \theta\text{ = }\frac{HYP}{\text{OPP}}\text{ = }\frac{25}{7} \\ \tan \theta\text{ = }\frac{O\P P}{\text{ADJ}}\text{ = }\frac{7}{24} \\ \sin \text{ }\theta\text{ =}\frac{OP\P}{\text{Hyp}}\text{ = }\frac{7}{25} \\ \sec \text{ }\theta=\frac{HYP}{\text{ADJ}}\text{ =}\frac{25}{24} \\ \cot \text{ }\theta\text{ = }\frac{ADJ}{OP\P}\text{ =}\frac{24}{7} \\ \text{cos }\theta\text{ = }\frac{ADJ}{\text{HYP }}=\frac{24}{25} \end{gathered}[/tex]