Answer :
Answer:
-270.16kJ
Explanations:
The formula for calculating the mole of a compound is expressed as:
[tex]mole=\frac{mass}{molar\text{ mass}}[/tex]Determine the mole of 43g of CH3OH
[tex]\begin{gathered} mole\text{ of CH}_3OH=\frac{43g}{32.04g\text{/mol}} \\ mole\text{ of CH}_3OH=1.342moles \end{gathered}[/tex]If the heat of formation of 1 mol of CH3OH is -201.3KJ, the amount of heat formed by 1.342moles of the same compound is given as:
[tex]\begin{gathered} heat\text{ formed}=1.342moles\times-201.3kJ \\ heat\text{ formed}=-270.16kJ \end{gathered}[/tex]Therefore -270.16kJ heat is exchanged when 43g are formed'
