First equation:
[tex]y=\mleft(x+1\mright)^2[/tex]
Since it is of the form
[tex](x-h)^2=4a(y-k)[/tex]
Hence, it is a parabola and it is an open upward parabola.
The vertex of the given equation is, (-1, 0).
Second equation:
[tex]y+3=4\mleft(x+1\mright)^2[/tex]
Since it is of the form
[tex](x-h)^2=4a(y-k)[/tex]
Hence, it is a parabola and it is an open upward parabola.
The vertex of the this equation is, (-1, -3).
