Answer :

The value of z is 58 when z is  directly proportional to [tex]\sqrt{x}[/tex] and indirectly proportional to [tex]y^{3}[/tex]

We have :

z is directly proportional to [tex]\sqrt{x}[/tex]

z is inversely proportional to [tex]y^{3}[/tex]

Now, we introduce a constant of proportionality, then

[tex]z = k\frac{\sqrt{x} }{y^{3} }[/tex]

It is given that z = 248 when x is 9 and y is 4.

Then, Applying these values in the equation,

[tex]z = k\frac{\sqrt{x} }{y^{3} }[/tex]

[tex]248 = k\frac{\sqrt{9} }{\ 4^{3} } \\\\248 = k \frac{3}{64} \\\\k = \frac{248*64}{3} =\frac{15872}{3} =5290.67[/tex]

Now, we need to calculate the value of z when x = 64 and y =9.

[tex]z = k\frac{\sqrt{x} }{y^{3} }[/tex]

[tex]z =\frac{15872}{3} *\frac{\sqrt{64} }{9^{3} } = \frac{15872*8}{3*729} =\frac{126976}{2187} \\z = 58.05[/tex]

Hence, the value of z = 58.05

To read more about proportionality, visit https://brainly.com/question/8598338

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