Answered

A modified roulette wheel has 36 slots. One slot is 0, another is 00, and the others are numbered 1 through 34, respectively. You are placing a bet that the outcome is an odd number. (In roulette, 0 and 00 are neither odd nor even.)What is your probability of winning?



Answer :

Given:

Sample space, S= {0, 00, 1, 2, 3, 4, ...., 34}.

So, n(S)=36

To find the probability that an outcome is an odd number:

Favorable outcomes are,

A={1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31, 33}

So, n(A)=17

Then, the probability is,

[tex]\begin{gathered} P(A)=\frac{n(A)}{n(S)} \\ =\frac{17}{36} \end{gathered}[/tex]

Thus, the probability is,

[tex]\frac{17}{36}[/tex]

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