Solution
First find the difference
[tex]782-680=102[/tex][tex]\begin{gathered} \text{ \% increase=}\frac{102}{680}\times100\text{ \%} \\ \\ \operatorname{\%}\imaginaryI\text{ncrease=0.15\times100{\operatorname{\%}}} \\ \\ \operatorname{\%}increase=15\text{ \%} \\ \end{gathered}[/tex]
The final answer
The few percent more expensive upgraded model of the TV is
[tex]15\text{ \%}[/tex]
