Answer :
There are 45 ways that joey select 1 that will run on his operating system and 1 that will not
To solve this problem the formula and the combination procedure we must use is:
C(n/r) = n! / [(n-r)! *r!]
Where:
- C(n/r) = combination
- n = total number of objects
- r = number of selected objects
- ! = factorial of the number
Information about the problem:
Run on
- n = 9
- r = 1
- C(9/1) =?
Will not run on
- n = 5
- r = 1
- C(5/1)=?
C(9/1) * C(5/1) = ?
Applying the combination formula we have:
C(n/r) = n! / [(n-r)! *r!]
C(9/1) = 9! / [(9-1)! *1!]
C(9/1) = 9! / [(8)! *1!]
C(9/1) = 9*8! / [(8)! *1!]
C(9/1) = 9/1!
C(9/1) = 9/1
C(9/1) = 9
C(5/1) = 5! / [(5-1)! *1!]
C(5/1) = 5! / [(4)! *1!]
C(5/1) = 5*4! / [(4)! *1!]
C(5/1) = 5/1!
C(5/1) = 5/1
C(5/1) = 5
C(9/1) * C(5/1) = 9*5 = 45
What is a combination?
In mathematics, a combination or combinations are all the possible groupings that can be made of a given number of elements, without repeating them and regardless of the order in which they are found.
Learn more about combination at: brainly.com/question/11732255
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