joey finds 14 video games that he would like to have. nine of them will run on this operating system and 5 will not. how many ways can joey select 1 that will run on his operating system and 1 that will not?



Answer :

There are 45 ways that joey select 1 that will run on his operating system and 1 that will not

To solve this problem the formula and the combination procedure we must use is:

C(n/r) = n! / [(n-r)! *r!]

Where:

  • C(n/r) = combination
  • n = total number of objects
  • r = number of selected objects
  • ! = factorial of the number

Information about the problem:

Run on

  • n = 9
  • r = 1
  • C(9/1) =?

Will not run on

  • n = 5
  • r = 1
  • C(5/1)=?

C(9/1) * C(5/1) = ?

Applying the combination formula we have:

C(n/r) = n! / [(n-r)! *r!]

C(9/1) = 9! / [(9-1)! *1!]

C(9/1) = 9! / [(8)! *1!]

C(9/1) = 9*8! / [(8)! *1!]

C(9/1) = 9/1!

C(9/1) = 9/1

C(9/1) = 9

C(5/1) = 5! / [(5-1)! *1!]

C(5/1) = 5! / [(4)! *1!]

C(5/1) = 5*4! / [(4)! *1!]

C(5/1) = 5/1!

C(5/1) = 5/1

C(5/1) = 5

C(9/1) * C(5/1) = 9*5 = 45

What is a combination?

In mathematics, a combination or combinations are all the possible groupings that can be made of a given number of elements, without repeating them and regardless of the order in which they are found.

Learn more about combination at: brainly.com/question/11732255

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