13/(x-2) is the inverse of the function H(x) =13/x+2
What is an inverse function?
In mathematics, the inverse function of a function f (also called the inverse of f) is a function that undoes the operation of f
Given H(x) =13/x+2
Let H(x) = y
So we can say y = 13/x+2
We will then make x the subject:
Since y = 13/x+2
y = (13 + 2x)/x
xy = 13 + 2x
xy - 2x = 13
x(y-2) = 13
x = 13/(y-2)
since x = H⁻¹(y) = 13/(y-2)
Thus H⁻¹(x) = 13/(x-2) (Replace y with x)
Therefore, the inverse of H(x) =13/x+2 is 13/(x-2)
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