The number of silicon atoms in 28.0855 g of silicon will be 6.022 × 10²³.
The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.
The atomic mass of silicon = 28.0855 amu
Using the mole concept that 1 mole = 6.022 × 10²³.
This number is called Avogadro's number.
1 mole / 28.0855g of silicon contains 6.022 × 10²³ atoms of silicon
The number of atoms present in a 28.0855 g of silicon will be calculated as,
Number of atoms of silicon = 6.022 × 10²³ × 28.0855 / 28.0855
Number of atoms of silicon = 6.022 × 10²⁰
Therefore, the number of silicon atoms in 28.0855 g of silicon will be 6.022 × 10²³.
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