Step 1
Given;
[tex]\begin{gathered} C(x)=10x+600 \\ x=number\text{ of items} \end{gathered}[/tex]Step 2
The fixed cost is determined when zero items are produced. Therefore, the fixed cost will be;
[tex]C(x)=10(0)+600=\text{ \$}600[/tex]Step 3
Find the cost of making 25 items
[tex]C(25)=10(25)+600=250+600=\text{ \$}850[/tex]Step 4
Suppose the maximum cost allowed is $1600
[tex]\begin{gathered} C(x)=1600 \\ 1600=10x+600 \\ 1600-600=10x \\ 1000=10x \\ x=100\text{ items} \end{gathered}[/tex]The domain and range of the cost function when will be;
[tex]\begin{gathered} Domain=[0,100] \\ Range=[600,1600] \end{gathered}[/tex]