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Solve the following system of linear equations by substitution and determine whether the system has one solution,no solution, or an infinite number of solutions. If the system has one solution, find the solution.5 - 2x + y = 410x + 2y = -6

Solve the following system of linear equations by substitution and determine whether the system has one solutionno solution or an infinite number of solutions I class=


Answer :

Given

- 2x + y = 4 (1)

10x + 2y = -6 (2)

Answer

-2/10 = -1/5

1/2

4/6 = 2/ 3

System has one solution

Multiply eq 1 by 5

-10x+5y=20

10x+2y=-6

Adding

7y =14

y=14/7 = 2

Put in eq 1

-2x+ 2 =4

-2x = 2

x= -1, y=2

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