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Use the formula to calculate the stopping distance for a vehicle traveling 45 mph. The tires have a coefficient of friction or 0.8 and the roadway has a grade of 0.15. Round your answer to one decimal place.

Use the formula to calculate the stopping distance for a vehicle traveling 45 mph The tires have a coefficient of friction or 08 and the roadway has a grade of class=


Answer :

[tex]\begin{gathered} d=\frac{v^2_o}{2g(f+G)} \\ \text{Where:} \\ v_o=45\text{mph} \\ f=0.8 \\ G=0.15 \\ g=\frac{9.8m}{s^2} \end{gathered}[/tex]

Therefore:

[tex]d=\frac{45^2}{2(9.8)(0.8+0.15)}=\frac{2025}{20.55}=98.54014599\approx98.5[/tex]

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