Explanation:
To determine if a bond is ionic or covalent we will have to find the electronegativity difference between the atoms that are participating in the bond.
P and O:
Electronegativity of P = 2.19
Electronegativity of O = 3.44
ED of O-P = 3.44 - 2.19
ED of O-P = 1.29
Since the electronegativiy difference between O and P is less than 2.1 the bond is covalent.
Ag and Ag:
Since we are considering the bond between two atoms of the same metal the bond is metallic.
Cl and Na:
Electronegativity of Cl = 3.16
Electronegativity of Na = 0.93
ED of Cl-Na = 3.16 - 0.93
ED of Cl-Na = 2.23
Since the electronegativiy difference between Cl and Na is greater than 2.1 the bond is ionic.
Answer:
O-P ---> covalent
Ag-Ag ---> metallic
Cl-Na ---> ionic
