Answer :
Answer:
The temperature is 2,231.36 K. (The closest value is 2,232.35K).
Explanation:
The given information from the exercise is:
- Initial temperature (T1): 80°C (353K)
- Initial volume (V1): 38.6mL
- Final volume (V2): 244mL
1st) It is necessary to convert the temperature unit from °C to K:
80+273 = 353K
2nd) Now we can calculate the final temperature (T2), by replacing the values of T1, V1 and V2 in the Charles's law formula:
[tex]\begin{gathered} \frac{V_1}{T_1}=\frac{V_2}{T_2} \\ \frac{38.6mL}{353K}=\frac{244mL}{T_2} \\ 0.10935\frac{mL}{K}=\frac{244mL}{T_2} \\ T_2=\frac{244mL}{0.10935\frac{mL}{K}} \\ T_2=2,231.36K \end{gathered}[/tex]So, the temperature is 2,231.36 K. (The closest value is 2,232.35K).
