tickets for a raffle cost $ 5. there were 832 tickets sold. one ticket will be randomly selected as the winner, and that person wins $ 1600 and also the person is given back the cost of the ticket. for someone who buys a ticket, what is the expected value (the mean of the distribution)?



Answer :

The most appropriate choice for expectation will be given by-

Expected value for someone who buys the ticket = $[tex](-1591.2)[/tex]

What is expectation?

At first it is important to know about probability of an event.

Probability gives us the information about how likely an event is going to occur

Probability is calculated by Number of favourable outcomes divided by the total number of outcomes.

Probability of any event is greater than or equal to zero and less than or equal to 1.

Probability of sure event is 1 and probability of unsure event is 0.

Suppose x is a random variable with the probability function f(x). suppose

[tex]x_1. x_2,........,x_n[/tex] are the values corrosponding to the actual occurance of the event and [tex]p_1, p_2.,,,, p_n[/tex] be the corrosponding probabilities.

Expectation is given by the formula [tex]p_1x_1+p_2x_2+...+p_nx_n[/tex]

Here,

Total number of tickets = 832

Number of prized tickets = 1

Probability of winning a ticket = [tex]\frac{1}{832}[/tex]

Probability of losing a ticket = [tex]\frac{831}{832}[/tex]

Gain of winning = $(1600 - 5) = $1595

Loss of losing = $(5 - 1600) = -$1595

Expected value for someone who buys the ticket

[tex]1595 \times \frac{1}{832} + (-1595)\times \frac{831}{832}[/tex]

[tex]1595\times(\frac{1-831}{832})\\-1595\times \frac{830}{832}\\[/tex]

$[tex](-1591.2)[/tex]

Expected value for someone who buys the ticket = $[tex](-1591.2)[/tex]

To learn more about expectation, refer to the link:

https://brainly.com/question/24305645

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