Answer :
The standard deviation of the sampling distribution is 0.0608.
What is standard deviation?
Standard Deviation is a measure which shows how much variation (such as spread, dispersion, spread,) from the mean exists. The standard deviation indicates a “typical” deviation from the mean. It is a popular measure of variability because it returns to the original units of measure of the data set.
p≈ N(p,[tex]\frac{\sqrt{p(1-p)} }{\sqrt{n} }[/tex])
For given problem, we will use the formula as
[tex]p' =X/n[/tex]
We have n = 200,
[tex]p_{1} =10/200[/tex] = 0.05
Similarly the value for next numbers are
0.045, 0.055, 0.035, 0.015, 0.06, 0.04, 0.03, 0.055.
Now p' = 0.045+0.055+0.035+ 0.015+0.06+ 0.04+0.03+0.055+0.050
= 0.0385
Now, standard deviation = [tex]\sqrt{\frac{p'(1-p')}{n} }[/tex]
= √((0.0385* (1 - 0.0385)) / 100
= 0.0608
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