Answer :
The magnetic field inside the given solenoid is 1.0048x10^-3 T whereas, magnetic field outside the given solenoid is zero.
What is magnetic field?
The magnetic influence on moving electric charges, electric currents, and magnetic materials is described by a magnetic field, which is a vector field. A force perpendicular to the charge's own velocity and the magnetic field acts on it when the charge is travelling through a magnetic field.
(1) You can use a long solenoid itself to get the directions as if directions as it behaves approximately as a bar magnet with north and south poles across its ends.
(2) a,
The formula to calculate the magnetic field of solenoid:
[tex]B = \mu_0 nl[/tex]
n = number of turns per unit. So,
[tex]B = \mu_0 \frac{N}{L} l[/tex]
putting the values
[tex]B = (4\pi \times 10^{-7}) \frac{400}{1 m } (2.0 A)[/tex]
[tex]B = 1.0048 \times 10^{-3} &[/tex] T
Therefore, The B inside the solenoid is 1.0048x10^-3 T
b, for ideal solenoid outside field is zero, same in this case.
(3) Iron is a ferromagnetic substance, which means that when an external magnetic field is introduced, it substantially polarizes in that direction, temporarily transforming it into a magnet. One way to conceptalise iron is as a collection of many domains, each of which has an average magnetic field strength of zero. The domains, however, arrange themselves in the direction of the applied magnetic field as soon as one is applied, considerably enhancing the field strength. To strengthen the magnetic field, an iron core is employed in solenoids.
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Complete Question
1) How can you make a compass without using iron or other ferromagnetic materials?
2) A 100 cm long solenoid has a total of 400 turns of wire and carries a current of 2.0 A.
What is the magnetic field a) inside the solenoid? b) outside the solenoid?
3) Why does the presence of iron inside a solenoid greatly increase the magnetic field?
