in unloading grain from the hold of a ship, an elevator lifts the grain through a distance of 12 m. grain is discharged at the top of the elevator at a rate of 2.0 kg each second, and the discharge speed of each grain particle is 3.0 m/s. find the minimum-horsepower motor that can elevate grain in this way.



Answer :

The minimum-horsepower motor that can elevate grain in this way is 249 W.

What is motor?

Energy is transformed into motion by mechanical or electromechanical devices known as motors. Energy in the form of rotational or linear motion—whether it be electrical, hydraulic, or pneumatic—is output to a shaft or other power transmission component where it performs meaningful work. Electrical motors come in AC or DC forms, and are further divided into specialised motors for particular applications, such as gearmotors, stepper motors, servomotors, and linear motors. Oil or air is the source of power for hydraulic and pneumatic motors. Outboard motors for boats and rocket motors are two examples of chemical motors. Both involve internal combustion and are frequently referred to as engines. Trolling motors are electric propulsion systems used to move small fishing boats. The last group is not covered in this article.

We know that,

The work done by motor is equal to Change in Mechanical energy

Then, the power output of the motor can be calculated using the formula:

[tex]P = \frac{ \triangle K + \triangle U }{t}[/tex]

[tex]P = \frac{\frac{1}{2}m(v_f^2 + v_i^2+gh) }{y}[/tex]

putting the values from question:

[tex]P = 2[\frac{1}{2}(3^2)+10(12) ][/tex]

P = 249 watt

Therefore, power is 249 watt.

To know more about motor, go to link

https://brainly.com/question/866077

#SPJ4

Other Questions