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27-10-2022
Physics

Answered

a 63 kg runner taking part in a 200 m dash must run around the end of a track that has a circular arc with a radius of curvature of 28 meters. if he completes the 200 m dash in 25.01 s and runs at constant speed throughout the race, what is the magnitude of his centripetal force as he runs the curved portion of the track?

Answer :

31-10-2022

The magnitude of the centripetal force as the runner moves on the curved portion is 144 N.

The mass of the runner is 63kg, the track length is 200m and the radius of the track is 28 meters. He completes the track in 25.01 seconds.

We know the centripetal force is given by.

F = MV²/R

Where,

M is the mass of the runner,

R is the radius of the track,

Vis the speed of the runner.

We also know,

Speed = Distance covered/time taken

V = D/t

So, putting the value of V in F,

F = M(D/t)²/R

Now, putting all the values,

F = 63 x 200 x 200(25.01 x 25.01 x 28)

F = 144 Newtons,

So, the centripetal force as he moves is 144n.

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