a 26 g ball of clay traveling east at 3.5 m/s collides with a 35 g ball of clay traveling north at 2.6 m/s . part a what is the movement direction of the resulting 61 g blob of clay? express your answer in degrees north of east.

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sirribel2049 sirribel2049

27-10-2022
Physics

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a 26 g ball of clay traveling east at 3.5 m/s collides with a 35 g ball of clay traveling north at 2.6 m/s . part a what is the movement direction of the resulting 61 g blob of clay? express your answer in degrees north of east.

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Qwbox Qwbox · Answer 1 · 2022-10-31T12:10:10-04:00

The speed of the 61g ball after collision is 0.4 m/s at an angle of 88.5° north of east.

Let us assume coordinates axes here, taking east as x axis and north as y axis.

So, the 26 g ball is moving with speed of 3.5m/s travelling in the x direction collides with 35g ball travelling with 2.6m/s in the y direction. After collision they collides with each other.

So, we know, the momentum is going to be conserved,

Hence,

Initial momentum = Final momentum

M₁V₁ + M₂V₂ = (M₁+M₂)V

M₁ is 26g,

M₂ is 35g,

V₁ is speed of 26g ball,

V₂ is speed of 35g ball.

V is the speed after collision.

Now, putting all the values,

(0.026)(3.5)i + (0.035)(2.6)j = (0.026 + 0.035)V

V = (0.091)i + (0.091)j

|V| = 0.4 m/s.

The angle between y axis and |V| is,

Tan A = 0.091/3.5

Tan A = 0.026

Hence the value of A is 1.5°.

Hence, the speed of the 61g ball is 0.4 m/s at an angle of 88.5° north of east.

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