The standard deviation of the thickness of layer 1 = 15.81 x 10⁻⁵ m
layer 2 = 20 x 10⁻⁵m
layer 3 = 17.32 x 10⁻⁵ m
The variance of the thickness of the three layers is 25,40 and 30 in nanometers
Let v₁, v₂, v₃ be the variance of the three layers of thickness.
Then, the standard deviation of the thickness of these layers can be found using the formula
v = σ²
Let us re-write this equation in order to find the standard deviation,
σ = √v
where v is the variance and
σ is the standard deviation
The standard deviation of layer 1 is
σ₁ = √v₁
= √(25 x 10⁻⁹)
= √(250 x 10⁻¹⁰)
= 15.81 x 10⁻⁵
The standard deviation of layer 2 is
σ₂ = √v₂
= √(40 x 10⁻⁹)
= √(400 x 10⁻¹⁰)
= 20 x 10⁻⁵
The standard deviation of layer 3 is
σ₃ = √v₃
= √(30 x 10⁻⁹)
= √(300 x 10⁻¹⁰)
= 17.32 x 10⁻⁵
Therefore, the standard deviation is 15.81 x 10⁻⁵m , 20 x 10⁻⁵ m, 17.32 x 10⁻⁵m
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