a brokerage survey reports that 30 percent of individual investors have used a discount broker; that is, one which does not charge the full commissions. in a random sample of 9 individuals, what is the probability that exactly two of the sampled individuals have used a discount broker



Answer :

The probability that precisely two of the sampled people utilized a discount broker is 0.2668.

A discount broker was employed by 30% of individual investors.

p = 30 ÷ 100 = 0.3

q = 1 - p

q = 1 - 0.3

q = 0.7

n = 9

P(x) = [tex]{}^{n}C_{x}p^{x}q^{n - x}[/tex]

Only two of the people polled had utilized a broker.

x = 2

P(2) = [tex]{}^{9}C_{2}[/tex](0.3)²[tex](0.7)^{7}[/tex]= 0.2668

Only three persons have used a deal broker.

= P(3) + P(2) + P(1) + P(0)

= [tex]{}^{9}C_{3}[/tex](0.3)³[tex](0.7)^{6}[/tex] +  [tex]{}^{9}C_{2}[/tex](0.3)²[tex](0.7)^{7}[/tex] + [tex]{}^{9}C_{1}[/tex](0.3)¹[tex](0.7)^{8}[/tex] + [tex]{}^{9}C_{0}[/tex](0.3)⁰[tex](0.7)^9[/tex]

= (84 × 0.027 × 0.1176) + (36 × 0.09 × 0.0823) + (9 × 0.3 × 0.0576) + (1 × 1 × 0.0403)

= 0.7291

Probability of a broker has been employed by at least three of them.

= P(2) - P(1) - P(0) - 1

= -([tex]{}^{9}C_{2}[/tex](0.3)²[tex](0.7)^{7}[/tex] -  [tex]{}^{9}C_{1}[/tex](0.3)¹[tex](0.7)^{8}[/tex] -  [tex]{}^{9}C_{0}[/tex](0.3)⁰[tex](0.7)^9[/tex]  - 1)

= -((36 × 0.09 × 0.0823) - (9 × 0.3 × 0.0576) - (1 × 1 × 0.0403) - 1)

= 0.9291

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