3. if the 90% confidence limits for the population mean are 34 and 46, which of the following could be the 99% confidence limits a) (36,41) b) (39,41) c) (30,50) d) (39,43) e) (38,45) 4. given that the population standard deviation is 7500 and a 95% confidence level. what should be the sample size if we want the margin of error to be m



Answer :

a) Option D, (39,43) could be the 99% confidence limit.

b) The determined minimum sample size is 166.

a) For a given sample size, the confidence interval is just the range of values including the real population mean. The confidence interval is interpreted as follows:

The real population mean are contained in around 95% of the estimated confidence intervals.

The breadth of the interval and the confidence level (including 95% or 99%) have a positive connection.

As the confidence level rises, the range of both the confidence interval expands, implying that the lower limit of the interval shrinks and the top bound of the interval expands.

Option B is the correct one among the available possibilities since it entirely follows the pattern. When compared to a 99% confidence interval, 33 should be less than 34, and 46 is more than 43.

b) s = Standard Deviation = $7,500 m = Margin of Error = $1,500 z = Empirical z-score at 95% CI = 2.575

The random sample for a 95% confidence interval is calculated as follows:

= (Z × s)² ÷ m²

= (2.575 × s)² ÷ m²

= (2.575 × 7500)² ÷ (1500)²

= 165.76

≈ 166

Learn more about the population mean and standard deviation at

https://brainly.com/question/18849331?referrer=searchResults

#SPJ4