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at 3:25 p.m., two trains left kalamazoo, michigan. one train traveled westward at a constant rate of 82 miles per hour, while the other traveled eastward at a constant rate of 66 miles per hour. if they are now 111 miles apart, what time is it now? show your work for how you solved this situation.



Answer :

Applying the physics of motion, the time now, when they are 111 miles apart, is 4:10 p.m.

Let the time taken for the trains to be 111 miles apart be T.

Then at that time, T, the faster train, which is 82 mph, should have traveled a distance of 82T miles.

D1 = 82T

At the same time, T, the slower train, which is 66 mph, should have traveled a distance of 66T miles.

D1 = 66T

The total distance traveled by both the trains is D1 + D2 = D = 82T + 66T.

D = 148T

From the data provided in the question, D = 111

Hence, 148T = 111

Solving the equation, the time T becomes

T = 111÷148

T = three and four hours

converting it into minutes,

T = 45 mins.

The current time = the time at which both the trains left + 45 mins.

The current time is 3:25 p.m. + 45 minutes.

The current time is 4:10 p.m.

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