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the number of hours spent per week on household chores by all adults has a mean of 26.3 hours and a standard deviation of 7.4 hours. the probability, rounded to four decimal places, that the mean number of hours spent per week on household chores by a sample of 46 adults will be more than 26.75 is:



Answer :

This question is about probability. The answer for this question is 34,09%.

Step-by-step explanation:

Suppose there was survey that state that the number of hours spent per week on house hold course of adult has mean 26,3 and standard deviatiador 7,4 and, sample are 46.

First, we need to know the base formula for probability given a mean and standard deviation.

First we need to know the z-score with this formula:

z-score =( x -μ )/ δ

Where:

X = individual data

μ = population mean

δ = population standard deviation.

But in this case, we were asked about the probabilty mean of 46 people. Then, we can use this formula :

Z-score =(x- μ) / (δ /√n)

Where :

X = sample mean

μ = population mean

δ = population standard deviation

Then we can find the z-score in z-table value.

Given :

X = 26,75

μ = 26,3

δ = 7,4

n = 46


Question :

Probability mean more than 26,75


Answer :

Z-score = (x- μ) / (δ /√n)

Z-score = (26,75 - 26,3)/ (7,4/√46)

Z-score = (0,45)/ (1,09)

Z-score = 0,4128


if we look in z-score table, we get number 0,6591.The probability that the mean hours spent per week on household chores by a sample of 46 adults will be more than 26.75 is 1 substract by the value of z-score ,

So, the probability mean for working adult more than 26,75 is 1 - 0,6591 = 0,3409 = 34,09%


Learn more about probabilty here :

brainly.com/question/15352354

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