find the confidence interval specified. assume that the population is normally distributed. a sociologist develops a test to measure attitudes about public transportation, and 27 randomly selected subjects are given the test. their mean score is 76.2 and their standard deviation is 21.4. construct the 95% confidence interval for the mean score of all such subjects.



Answer :

The 95% confidence interval for the mean score of all such subjects. will be ( 67. 7 , 84.7) using mean.

What is mean?

Mathematicians, particularly statisticians, use a variety of means. Every mean serves to condense a certain set of facts, frequently to help grasp the general significance of a particular data set.

sample mean = x' = 76.2

sample S = 21.4

sample size n = 27

Confidence level = a = 0.95
α=1-a=0.05
95% confidence interval for the mean score of all such subjects is
(x'-E , x'+E)
E = [tex]\frac{tc*s}{\sqrt{n}}[/tex]
E = [tex]\frac{2.056*21.4}{\sqrt{27}}[/tex]} = 8.466

95% confidence interval for the mean score of all such subjects is
(x'-E , x'+E)
=(76.2-8.466 , 76.2+8.466)
=(67.734 , 84.666)
= ( 67. 7 , 84.7)

Hence The answer will be ( 67. 7 , 84.7).

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