Determine the following elements using their quantum #s of the elements last placed e-.include the e- configuration of the last placed electron. n = 6 , l = 1, m = 0 , s = + ½



Answer :

According to the explanation given in our last session, now we have the following information about the last electron:

n = 6

l = 1

m = 0

s = +1/2

Now we know that this electron is located in the 6th shell, therefore the element is in the 6th period of the periodic table

l = 1, this means that the last orbital will be p

m = 0, this means that the electron is located in the middle of the orbital

s = +1/2, this means that the electron is pointing upwards

Gathering all these informations, we know have as the element in which this last electron belongs is Lead, Pb