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suppose a motor connected to a 120 v source draws 10.0 a when it first starts. (b) what current does it draw at its normal operating speed when it develops a 100 v back emf? (answer in a)



Answer :

ayune

Since the motor develops a 100 V back emf (electromotive force) at its normal operating speed, its current is 1.67 A.

The relation between current (I), voltage(V), and resistor (R) in a direct current circuit is:

V = I . R

At start:

V = 120 V

I = 10 A

Hence, we can find the equivalent resistor:

R = V/ I = 120 / 10 = 12 Ohm

When the motor is running, it develops 100 V back emf.

Therefore, the net voltage is

= 120 V - 100 V = 20 V

and hence, the current:

I = 20 / 12 = 1.67 A

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