Answer:
8 units.
Step-by-step explanation:
Given points:
Graph the given points (x, y) on the coordinate plane. (See attachment).
Distance between two points
[tex]\boxed{d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}[/tex]
where (x₁, y₁) and (x₂, y₂) are the endpoints.
Substitute the given points into the distance formula and solve for d:
[tex]\implies d=\sqrt{(-6-2)^2+(3-3)^2}[/tex]
[tex]\implies d= \sqrt{(-8)^2+(0)^2}[/tex]
[tex]\implies d=\sqrt{64+0}[/tex]
[tex]\implies d=\sqrt{64}[/tex]
[tex]\implies d=8\; \sf units[/tex]
Therefore, the distance between the two given points is 8 units.
As the two points have the same y-value, the two points are on a horizontal line. Therefore, the distance between them can be calculated by simply determining the difference in their x-values:
[tex]\implies 2-(-6)=8\; \sf units[/tex]
