suppose you are collecting a gas over water at 23 oc and obtain a pressure reading of 784.0 mm hg. if the vapor pressure of water is 21.1 mm hg at the collection temperature, what is the pressure of the collected gas? type answer



Answer :

The pressure of the collected gas is  762.9 mmHg

According to Dalton's law of partial pressures, an ideal gas's partial pressure—or pi—in a mixture of ideal gases is equal to the pressure the gas would experience if it were the only thing in the combination's volume and temperature.

The most frequent occurrence of Dalton's law of partial pressures is when a gas is captured by displacing water. The sum of the partial pressure of the gas itself plus the vapor pressure of water at that temperature determines the overall pressure that a wet gas exerts.

Given Data:

The gaseous mixture's total pressure (P) i= 784 mmHg.

Water vapour partial pressure (pH2O) = 21.1 mmHg

Partially collected gas pressure (pGas) = ?

Calculation of the gas collected partial pressure:

The gas collected and the water vapor combined have the same total pressure as the gaseous mixture.

P = pH₂O + pGas

pGas = P - pH₂O

pGas = 784 mmHg - 21.1 mmHg = 762.9 mmHg

Therefore, the Pressure of collected gas = 762.9 mmHg

To know more about Dalton's law, refer to this link:

https://brainly.com/question/14119417

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